(v-4)^2=2v^2-4v-5

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Solution for (v-4)^2=2v^2-4v-5 equation: 



(v-4)^2=2v^2-4v-5

We move all terms to the left:

(v-4)^2-(2v^2-4v-5)=0

We get rid of parentheses

-2v^2+(v-4)^2+4v+5=0

We add all the numbers together, and all the variables

-2v^2+4v+(v-4)^2+5=0

We move all terms containing v to the left, all other terms to the right

-2v^2+4v+(v-4)^2=-5

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